prove that sin(90-a)/cosec(90-a) + cos(90-a)/sec(90-a)=1

Prove the following: i sin θ sin90o θ cos θ cos 90o θ=0 ii cos90o θsec90o θtan θ/cosec90osin90o θcot90o θ+tan 90o θ/cot θ=2 iii tan 90o Acot A/cosec2 A cos2 A=0 iv

i) cos A/ (1 – sin A) + cos A/ (1 + sin A) = 2 sec A (ii) cos A/ (cosec A + 1) + cos A/ (cosec A – 1) = 2 tan A - Noon Academy

Someone please solve this 17 18 19 sin 0 cos (90' — 0) cos0 cose sin(90• — - Maths - Polynomials - 13377039

Prove rightarrow sin (90^{o}-theta)cos (90^{o}-theta)=dfrac {tan theta}{1+tan ^{2}theta}

Answered: Sin (0)=cos(90-0) Cos (0)= Sin (90-0)…

दिखाइए कि :(cos(90^(@) - theta) . sec (90^(@) - theta)tan theta )/(cosec(90^(@) - 0 )sin(90^(@)

Prove that sinA cos(90-A) + sin(90-A)cosA=1

5.trigonometry at A Glance 1, PDF, Trigonometric Functions

prove that sin(90-a)/cosec(90-a) + cos(90-a)/sec(90-a)=1

sin A sin (90°- A) + :) Prove that: cos A - = sec A cosec A. cos (90° - A) Huide the line seo